Hello, Frank, Steve and the list;
"Meteoroids of smaller intial mass lose all of their cosmic velocity while
still several kilometers above the Earth. At this point the meteoroid´s
fall path becomes quite steep since its forward momentum has ceased
and the body falls by gravity alone, which is the terminal velocity of the
meteoroid. It varies somewhat depending upon the shape of the of the
falling meteoroid creating air resistance around it, but is typically between
125 meters (410.10 feet) and 250 meters (820.20 feet) / second, when it
impacts."
(Norton O.R. (2002) The Cambridge Encyclopedia of Meteorites,
Cambridge University Press)
take care,
pekka
[EMAIL PROTECTED] wrote:
In a message dated 6/6/03 10:21:17 AM Central Daylight Time, [EMAIL PROTECTED] writes:
Does anyone know of a
measurement of terminal velocity from any fall, catching one on radar or
something?
Hello Frank and list,
I have also heard the number "122 miles per hour" tossed around as the speed.
So would 122 miles x 5,280 ft/mile = 644,160 feet /hr. / 3,600 seconds per hour = 178.93 feet per second.
12 miles up x 5,280 feet per mile = 63,360 feet / 178.93 = 354 seconds = 5 minutes 54 seconds.
Sounds a little closer.
Now, did the fireball extinguish at 12 mile up, or possible higher or lower?
Steve Arnold
--
Pekka Savolainen Jokiharjuntie 4 FIN-71330 Rasala FINLAND + 358 400 818 912 Group Home Page: http://www.smartgroups.com/groups/eurocoin Group Email Address: [EMAIL PROTECTED]
