<http://stackoverflow.com/questions/28570523/handling-exceptions-under-mod-wsgi-assigning-to-sys-excepthook-doesnt-work#>
I want to generate an html page with http response status '200 OK' in case
of an uncaught exception in my wsgi application, instead of web server's
standard '500 Internal Server Error' response for such case. To do so, I've
made the following sample code:
def application(environ, start_response):
def exception(etype, evalue, trace):
start_response('200 OK', [('Content-Type', 'text/plain')])
return ['Error']
sys.excepthook = exception
...
But the function 'exception' is never called, and a standard '500 Internal
Server Error' response is still generated by server in case of an uncaught
exception.
I looked through the documentation, but unable to find the answer. Are
there any ways to handle uncaught by try..except exceptions under mod_wsgi?
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