I created test.py
raise ValueError("throwing up")
I ran it by running
$> python test.py > /dev/null 2>&1
$> echo $?
1
Not sure what else you might be doing wrong
On Mon, Feb 8, 2016 at 3:13 PM, Vikram Kone <[email protected]> wrote:
> For testing it I simply did this in the python script
>
> #my_program.py
> #!/usr/bin/python
>
> raise ValueError("throwing up")
>
>
> On Mon, Feb 8, 2016 at 10:39 AM, Russell Simpkins <
> [email protected]> wrote:
>
>> Virkam,
>>
>> You don't show your python. Are you using "exit(1)" in your python when
>> there is an error condition?
>> You need to exit(1) or something other than zero.
>>
>> Russ
>>
>> On Mon, Feb 8, 2016 at 1:06 PM, Vikram Kone <[email protected]> wrote:
>>
>>> Hi,
>>> I have a python script that I use as to check certain system conditions
>>> to alert on using monit.
>>> This script prints a buch of stuff during execution to stdout which I
>>> want to capture in a log file.
>>> How should I configure the monit conf script, such that I can capture
>>> both the stdout and stderr of this script and at the same time alerting on
>>> the exit status of the script. The monit alert should also included the
>>> stdout/stderr for the alert events.
>>>
>>> This is what I tried
>>>
>>> #/etc/monit/conf/myprogram.conf
>>>
>>> check program my_program with path "/usr/bin/python -u
>>> /opt/program/my_program.py > my_prgoram.log 2&>1"
>>> if status !=0 alert
>>>
>>> But I see that the monit always thinks that the program is reporting
>>> status=0 even when then it exists with error code 1.
>>>
>>> What am i doing wrong?
>>>
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>>
>>
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