yes, it works when I run the python command directly from shell.
but when I do

$> monit start my_program

I don't see the log file being created

On Mon, Feb 8, 2016 at 12:22 PM, Russell Simpkins <[email protected]
> wrote:

> I created test.py
>
> raise ValueError("throwing up")
>
> I ran it by running
>
> $> python test.py > /dev/null 2>&1
> $> echo $?
> 1
>
> Not sure what else you might be doing wrong
>
>
> On Mon, Feb 8, 2016 at 3:13 PM, Vikram Kone <[email protected]> wrote:
>
>> For testing it I simply did this in the python script
>>
>> #my_program.py
>> #!/usr/bin/python
>>
>> raise ValueError("throwing up")
>>
>>
>> On Mon, Feb 8, 2016 at 10:39 AM, Russell Simpkins <
>> [email protected]> wrote:
>>
>>> Virkam,
>>>
>>> You don't show your python. Are you using "exit(1)" in your python when
>>> there is an error condition?
>>> You need to exit(1) or something other than zero.
>>>
>>> Russ
>>>
>>> On Mon, Feb 8, 2016 at 1:06 PM, Vikram Kone <[email protected]>
>>> wrote:
>>>
>>>> Hi,
>>>> I have a python script that I use as to check certain system conditions
>>>> to alert on using monit.
>>>> This script prints a buch of stuff during execution to stdout which I
>>>> want to capture in a log file.
>>>> How should I configure the monit conf script, such that I can capture
>>>> both the stdout and stderr of this script and at the same time alerting on
>>>> the exit status of the script. The monit alert should also included the
>>>> stdout/stderr for the alert events.
>>>>
>>>> This is what I tried
>>>>
>>>> #/etc/monit/conf/myprogram.conf
>>>>
>>>> check program my_program with path "/usr/bin/python -u
>>>> /opt/program/my_program.py > my_prgoram.log 2&>1"
>>>>  if status !=0 alert
>>>>
>>>> But I see that the monit always thinks that the program is reporting
>>>> status=0 even when then it exists with error code 1.
>>>>
>>>> What am i doing wrong?
>>>>
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>>>>
>>>
>>>
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