and how does timeout comes into play here
On Wed, Aug 10, 2016 at 11:38 PM, Vikram Kone <[email protected]> wrote: > Do you mean this one? > > if status !=0 for 2 times within 2 cycles then alert > > > On Wed, Aug 10, 2016 at 11:06 PM, Martin Pala <[email protected]> > wrote: > >> The second configuration is correct. >> >> The combination of "every" with "X cycles" is confusing, we'll modify the >> syntax: https://bitbucket.org/tildeslash/monit/issues/174/th >> e-for-x-cycles-is-confusing-if-the-test >> >> Best regards, >> Martin >> >> >> On 11 Aug 2016, at 04:48, Vikram Kone <[email protected]> wrote: >> >> I have a monit check program as follows >> >> check program test_pgm with path "/bin/bash /var/run/test.sh" >> every 2 cycles >> if status !=0 for 2 cycles then alert >> >> Let's say my monit daemon is set to run every 60 seconds which means each >> cycle is 1 minute. I want to run my program every 2mins and alert if it >> fails twice in a row >> >> Is what I have above correct? or should I say >> >> if status !=0 for 4 cycles then alert >> >> or should it be >> >> if status !=0 for 2 times within 2 cycles then alert >> >> -- >> To unsubscribe: >> https://lists.nongnu.org/mailman/listinfo/monit-general >> >> >> >> -- >> To unsubscribe: >> https://lists.nongnu.org/mailman/listinfo/monit-general >> > >
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