yes

> On 11 Aug 2016, at 08:54, Vikram Kone <[email protected]> wrote:
> 
> check program test_pgm with path "/bin/bash /var/run/test.sh"
> with timeout 3600 seconds
> every 2 cycles
> if status !=0 for 2 cycles then alert
> In this case let's say test.sh takes 45 mins to finish (either success or 
> failure) each time. Will the above config, still holds correct ie, will it 
> alert if the pgm failed twice consecutively?
> 
> On Wed, Aug 10, 2016 at 11:51 PM, Vikram Kone <[email protected] 
> <mailto:[email protected]>> wrote:
> and how does timeout comes into play here
> 
> 
> 
> On Wed, Aug 10, 2016 at 11:38 PM, Vikram Kone <[email protected] 
> <mailto:[email protected]>> wrote:
> Do you mean this one?
> if status !=0 for 2 times within 2 cycles then alert
> 
> On Wed, Aug 10, 2016 at 11:06 PM, Martin Pala <[email protected] 
> <mailto:[email protected]>> wrote:
> The second configuration is correct.
> 
> The combination of "every" with "X cycles" is confusing, we'll modify the 
> syntax: 
> https://bitbucket.org/tildeslash/monit/issues/174/the-for-x-cycles-is-confusing-if-the-test
>  
> <https://bitbucket.org/tildeslash/monit/issues/174/the-for-x-cycles-is-confusing-if-the-test>
> 
> Best regards,
> Martin
> 
> 
>> On 11 Aug 2016, at 04:48, Vikram Kone <[email protected] 
>> <mailto:[email protected]>> wrote:
>> 
>> I have a monit check program as follows
>> 
>> check program test_pgm with path "/bin/bash /var/run/test.sh"
>> every 2 cycles
>> if status !=0 for 2 cycles then alert
>> Let's say my monit daemon is set to run every 60 seconds which means each 
>> cycle is 1 minute. I want to run my program every 2mins and alert if it 
>> fails twice in a row
>> 
>> Is what I have above correct? or should I say
>> 
>> if status !=0 for 4 cycles then alert
>> or should it be
>> 
>> if status !=0 for 2 times within 2 cycles then alert
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