If you were to leave the parentheses you'd be calling the function at that
very instant :D
On Wed, Oct 1, 2008 at 6:16 PM, VirtuosiMedia <[EMAIL PROTECTED]>wrote:
>
> Thanks, that did the trick. I had tried adding this as a parameter,
> but I didn't know to remove the parentheses.
>
> On Oct 1, 2:13 pm, "Guillermo Rauch" <[EMAIL PROTECTED]> wrote:
> > this.completed.delay(delayLength, this);
> >
> > On Wed, Oct 1, 2008 at 6:11 PM, VirtuosiMedia <[EMAIL PROTECTED]
> >wrote:
> >
> >
> >
> >
> >
> > > delay() is something that I've been trying to use because it would
> > > work great, but so far I've been unsuccessful.
> >
> > > this.completed().delay(delayLength);
> >
> > > On Oct 1, 1:56 pm, "Guillermo Rauch" <[EMAIL PROTECTED]> wrote:
> > > > If all the animations have the same duration, you could just trigger
> a
> > > timer
> > > > or use chain() when index == 0 in the loop.
> > > > Otherwise, you might want to check Group out.
> >
> > > > On Wed, Oct 1, 2008 at 5:49 PM, VirtuosiMedia <
> [EMAIL PROTECTED]
> > > >wrote:
> >
> > > > > I'm having a little trouble with executing a function at the proper
> > > > > time once the animations in an each loop have completed. Rather
> than
> > > > > running after all animation is done, it instead runs instantly
> after
> > > > > the calculations are done. I know that this is a common thing to
> do,
> > > > > but I'm struggling with it for some reason. Here's the relevant
> code
> > > > > using (the animations use Morph):
> >
> > > > > xValues.each(function(item, index){
> > > > > animated.start({
> > > > > 'top': yValues[index],
> > > > > 'left': item
> > > > > });
> > > > > });
> > > > > //I would like to run this function after the above animations have
> > > > > finished
> > > > > this.completed();
> >
> > > > --
> > > > Guillermo Rauchhttp://devthought.com
> >
> > --
> > Guillermo Rauchhttp://devthought.com
>
--
Guillermo Rauch
http://devthought.com
