I'd say (to get a grasp of how compute() really works) use FF &
Firebug, use breakpoints to break & step through the code, and check
what this.parent refers to. Depending how compute() gets call, i.e.
through delays/periodicals, you might need to use something like
arguments.callee.parent instead.
On Oct 21, 11:35 pm, "Iván N Paz" <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> Im extending Fx.Morph onto another class that will basicly have the same
> functionality plus other stuff it doesnt do right now (i.e. bezier pathing)
>
> Maybe I've gotten wrong the whole implement/extend deal, and have surfed a
> lot thru all the threads in here that treat such subject, and Aaorons book
> as well....
>
> Well... to the point... this is what I have:
>
> Fx.MorphPath = new Class({
>
> Extends: Fx.Morph,
>
> compute: function(from, to, delta){
> var now = {};
> //check if we have a motion path
> var mp = (this.options.motionpath ? this.options.motionpath : false
> );
> for (var p in from)
> {
> //motionpath is only applied to top/left css properties
> if(mp) {
> var coords = mp.getCoordinates(1-delta);
> var x = coords.x + 'px';
> var y = coords.y + 'px';
> }
>
> //Go rewriting as usual, but take motionpath in consideration now...
> if(p == 'left' && mp){
> //calculate X movement (left)
> now[p] = x;
> }else if(p == 'top' && mp){
> //calculate Y movement (top)
> now[p] = y;
> }else{
> //standard mootool calculation
> now[p] = this.parent(from[p], to[p], delta);
> }
> }
> return now;
> }
>
> });
>
> So, where's the problem... the problem lies, in that I can do the bezier
> pathing morphin thingy without problem BUT if I try to also morph another
> property such as width, opacity, whatever, it breaks....
>
> I suspect the problem is here:
>
> //standard mootool calculation
> now[p] = this.parent(from[p], to[p], delta);
>
> Im trying to let normal Fx.Morph do the rest of the calculation and
> cascading... but this is breaking as hell...
>
> Am I making some stupid mistake, bad concept or anything??? SHould I do
> implement instead? Any ideas?
>
> Thanks for your time
> Iván
