hi cyrine
It's the 3rd column that should sum to 1, not the 1st. The 1st column is
p(f|e). The 3rd column is p(e|f). See
http://www.statmt.org/moses/?n=FactoredTraining.ScorePhrases
On 18/01/2011 15:20, Cyrine NASRI wrote:
Hello everyone,
I have a question about the generation of translation table
I followed the tutorial using the latest version of Moses
I got one:
translation table in this format:
a a and so on ||| etc ||| 0.0008285 2.02489e-05 1 0.0067199 2.718 |||
||| 1207 1
a a competitions for nationals of ||| concours a a pour les
ressortissants des ||| 0.333333 2.06671e-06 1 5.37794e-07 2.718 |||
||| 3 1
a a competitions for nationals ||| concours a a pour les
ressortissants ||| 0.333333 7.97295e-06 1 3.25607e-06 2.718 ||| ||| 3 1
a a competitions for ||| concours a a pour ||| 0.333333 3.06388e-05 1
8.06435e-05 2.718 ||| ||| 3 1
a a competitions ||| concours a a ||| 0.333333 9.31982e-05 1
0.000284839 2.718 ||| ||| 3 1
a a new paragraph i ||| a en un nouveau paragraphe que je ||| 1
0.00113574 1 4.77085e-08 2.718 ||| ||| 1 1
a a new paragraph ||| a en un nouveau paragraphe que ||| 1 0.00130408
0.5 7.55146e-08 2.718 ||| ||| 1 2
a a new paragraph ||| a en un nouveau paragraphe ||| 0.5 0.00130408
0.5 2.4472e-06 2.718 ||| ||| 2 2
a a new ||| a en un nouveau ||| 0.5 0.00214159 1 5.49442e-06 2.718 |||
||| 2 1
a a pizza service without delivery ||| un service pizza sans livraison
||| 1 0.0135509 1 0.0130115 2.718 ||| ||| 1 1
a a pizza service without ||| un service pizza sans ||| 1 0.0508158 1
0.089454 2.718 ||| ||| 1 1
a a pizza service ||| un service pizza ||| 1 0.14029 1 0.127362 2.718
||| ||| 1 1
a a question ||| concernant un point ||| 0.25 0.000148039 0.166667
4.41548e-07 2.718 ||| ||| 4 6
a a question ||| des problèmes concernant un point ||| 0.5 0.000148039
0.166667 2.34826e-12 2.718 ||| ||| 2 6
a a question ||| portant sur des problèmes concernant un point ||| 0.5
0.000148039 0.166667 1.60332e-18 2.718 ||| ||| 2 6
a a question ||| problèmes concernant un point ||| 0.5 0.000148039
0.166667 1.15288e-10 2.718 ||| ||| 2 6
my problem is that for example in these three lines:
a a new paragraph i ||| a en un nouveau paragraphe que je ||| 1
0.00113574 1 4.77085e-08 2.718 ||| ||| 1 1
a a new paragraph ||| a en un nouveau paragraphe que ||| 1 0.00130408
0.5 7.55146e-08 2.718 ||| ||| 1 2
a a new paragraph ||| a en un nouveau paragraphe ||| 0.5 0.00130408
0.5 2.4472e-06 2.718 ||| ||| 2 2
the prob (a a new paragraph i / a en un nouveau paragraphe que je) =1
and ,
the prob (a a new paragraph ||| a en un nouveau paragraphe que ) = 1
and,
the prob ( a a new paragraph ||| a en un nouveau paragraphe) = 0.5
wich is false because the sum of three probabilities > 1
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