From: Robert Hegemann <[EMAIL PROTECTED]>
>Mark wrote:=20
>> The energy of this wave shows up in scalefactor band (sfb) =3D 12,
>> with an energy of -10db. The dynamic range of a CD is 96db,
>> meaning that the energy range in sfb=3D12 is: -106 -> -10 (db). =20
>
>This is true for L/R channels. But, what would the situation be
>in MS stereo? As with M=3D(L+R)/sqrt2 and S=3D(L-R)/sqrt2
>the dynamic range for the mid channel M would go up=20
>to (96+96)/sqrt2 =3D 136 db and for the side channel S down=20
>to (96-0 )/sqrt2 =3D 68 db. So we have to consider this computing
>the ATH.
I disagree that the dyn. range of (L-R)/sqrt2 is less than that of the sum.
What if the right channel is the exactly opposite of the left ?
Then of both have a 60 units of energy , then the sum , I mean , difference
will have 120 units !
Notice that Bells are logaritmic, so you can't just add and substract them.
I think that adding ( or substracting ) two 96 dB channels gives you one with
102 bB. ( + 6 dB is x2 absolute; I think )
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David Balazic , student
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