In the following the quarter wave thickness seems to the be the fraction of the lower refractive index to the total refractive index. Why/how is this related to the quarter wave Why does this wave maxmize the band gap. BEcause the reflection leading to destructive interference is maximized at this quarter wave thickness. But how is the above formula related to the quarter of the wavelength? Thanks much. VR Sitaraman
; We'll make the default d1 equal to the quarter-wave thickness. You ; can change that by changing this line, or even easier, by running: ; mpb d1=0.3 bandgap1d.ctl ; or whatever. (define-param is a command to define parameters that ; can be varied from the command line like this.) (define-param d1 (/ (sqrt eps2) (+ (sqrt eps1) (sqrt eps2)))) (define d2 (- 1 d1)) ____________________________________________________________________________________ Food fight? Enjoy some healthy debate in the Yahoo! Answers Food & Drink Q&A. http://answers.yahoo.com/dir/?link=list&sid=396545367 _______________________________________________ mpb-discuss mailing list [email protected] http://ab-initio.mit.edu/cgi-bin/mailman/listinfo/mpb-discuss
