Hi,

the definition of NULL is not the problem, the problem is why the NULL macro is 
expanded to 0 and not to another value. 
I would prefer 42 (see the hitchhikers guide through the galaxy) and i think 
chinese would prefer 666.

Rolf F.


mspgcc-users@lists.sourceforge.net schrieb am 29.03.04 09:49:56:
> 
> Hello, 
> 
> Here some info 
> 
> From The book "The C programming language" by Brain W. Kernighan and Dennis
> M. Ritchie" ISBN 0-13-110370-9 ISBN 0-13-110362-8
> Page 102 Chapter 5.4
> 
> "Pointers and integers are not interchangeable. Zero is the sole exception:
> the constant zero may be assigned to a pointer, and a pointer may be
> compared with the constant zero. The symbolic constant NULL is often used in
> place of the Zero, as a mnemonic to indicate more clearly that this is a
> special value for a pointer. NULL is defined in <stdio.h>. "
> 
> Robert
> 
> 
> -----Original Message-----
> From: mspgcc-users-ad...@lists.sourceforge.net
> [mailto:mspgcc-users-ad...@lists.sourceforge.net] On Behalf Of
> nobo...@web.de
> Sent: 2004 March 28 00:34
> To: mspgcc-users@lists.sourceforge.net
> Subject: Re: [Mspgcc-users] Why #define NULL 0?
> 
> Hi,
> 
> > as far as i know the compiler does if(!foo) => if(0==foo) =>if(NULL==foo)
> at compile time.
> 
> i forgot to say that chapter 6.5.3 (C99) says that the unary operator ! can
> be applied to a pointer type; that's the reason why it works although on
> first look it seems to work only if the NULL macro is expanded to 0.
> 
> 
> > But generally it's not possible to compare a pointer with an integer,
> because they the have diffent type and often do not have the same size. On
> sparc64 the user-space pointer have 32 bit while the kernel-space pointers
> have 64 bit, so on that platform comparing integers with pointers is a bad
> idea.
> > Therefore gcc generally produces a warning if he finds such ugly code.
> > 
> > 
> > >> After all, ain't unary logical operations with pointers illegal?
> > 
> > A pointer is an object of size sizeof(pointer); there is no reason why not
> to apply logical operations with that object.
> 
> I forgot to say that maybe for some operators (look into the standard) you
> have to use a union to apply them (to the other member of the union):
> 
> union foo
> {
>   type *p_p;
>   char a_c[sizeof(type *)];
> };
> I
> If sizeof(int) == sizeof(type *) than you can use int as the second member.
> I
> Rolf F.
> 
> 
> 
> 
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