The obvious reason is that that macro expansion would be longer, but you
have the source, choose your poison.

Garst

nobo...@web.de wrote:
> 
> Hi,
> 
> the definition of NULL is not the problem, the problem is why the NULL macro 
> is expanded to 0 and not to another value.
> I would prefer 42 (see the hitchhikers guide through the galaxy) and i think 
> chinese would prefer 666.
> 
> Rolf F.
> 
> mspgcc-users@lists.sourceforge.net schrieb am 29.03.04 09:49:56:
> >
> > Hello,
> >
> > Here some info
> >
> > From The book "The C programming language" by Brain W. Kernighan and Dennis
> > M. Ritchie" ISBN 0-13-110370-9 ISBN 0-13-110362-8
> > Page 102 Chapter 5.4
> >
> > "Pointers and integers are not interchangeable. Zero is the sole exception:
> > the constant zero may be assigned to a pointer, and a pointer may be
> > compared with the constant zero. The symbolic constant NULL is often used in
> > place of the Zero, as a mnemonic to indicate more clearly that this is a
> > special value for a pointer. NULL is defined in <stdio.h>. "
> >
> > Robert
> >
> >
> > -----Original Message-----
> > From: mspgcc-users-ad...@lists.sourceforge.net
> > [mailto:mspgcc-users-ad...@lists.sourceforge.net] On Behalf Of
> > nobo...@web.de
> > Sent: 2004 March 28 00:34
> > To: mspgcc-users@lists.sourceforge.net
> > Subject: Re: [Mspgcc-users] Why #define NULL 0?
> >
> > Hi,
> >
> > > as far as i know the compiler does if(!foo) => if(0==foo) =>if(NULL==foo)
> > at compile time.
> >
> > i forgot to say that chapter 6.5.3 (C99) says that the unary operator ! can
> > be applied to a pointer type; that's the reason why it works although on
> > first look it seems to work only if the NULL macro is expanded to 0.
> >
> >
> > > But generally it's not possible to compare a pointer with an integer,
> > because they the have diffent type and often do not have the same size. On
> > sparc64 the user-space pointer have 32 bit while the kernel-space pointers
> > have 64 bit, so on that platform comparing integers with pointers is a bad
> > idea.
> > > Therefore gcc generally produces a warning if he finds such ugly code.
> > >
> > >
> > > >> After all, ain't unary logical operations with pointers illegal?
> > >
> > > A pointer is an object of size sizeof(pointer); there is no reason why not
> > to apply logical operations with that object.
> >
> > I forgot to say that maybe for some operators (look into the standard) you
> > have to use a union to apply them (to the other member of the union):
> >
> > union foo
> > {
> >   type *p_p;
> >   char a_c[sizeof(type *)];
> > };
> > I
> > If sizeof(int) == sizeof(type *) than you can use int as the second member.
> > I
> > Rolf F.
> >
> >
> >
> >
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