>very much like a log. You could use the taylor-series, which can be
>calculated quite quick, but is not a very good approximation. I don't know
>the taylor-series by heart, but I could look it up. In case you want to
>start programming, it will be of the form:
>y=a+bx+cx^2+dx^3+....


Taylors rule says that 

log (1+x) = x - x^2/2 + x^3/3 + .... + (x^(2n+1)) / (2n+1)!

so

log x = (x-1) - (x-1)^2/2 + ... +(-1)^n-1 * ((x-1)^n) / n

I hope to be helpful to you, bye
  Stefano
-------
Fronteddu Stefano
Student in Software Engineering
[EMAIL PROTECTED]
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ICQ: 21401454
0338/3645458


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