I.e. the ideal output would be:
+-------+---------------------+
| id | start_date |
+-------+---------------------+
| 109k7 | 2007-10-07 12:06:58 |
| s3x6 | 2007-10-07 08:58:20 |
| wt57 | 2007-10-07 15:57:37 |
| sxmns | 2007-10-06 02:17:30 |
+-------+---------------------+
What rule generates the order 109k7, s3x6, wt57, sxmns?
PB
Papalagi Pakeha wrote:
Hello,
I have a query like:
SELECT id, start_date FROM iddt WHERE id IN ('109k7','s3x6','sxmns','wt57');
which gives me:
+-------+---------------------+
| id | start_date |
+-------+---------------------+
| 109k7 | 2007-10-07 12:06:58 |
| sxmns | 2007-10-06 02:17:30 |
| wt57 | 2007-10-07 15:57:37 |
| s3x6 | 2007-10-07 08:58:20 |
+-------+---------------------+
How can I get the results sorted by the order in which they appear in
the ID list? Indeed I could do it in the application but prefer to get
the results in the right order from MySQL as the ID list may be long
and I may need only first few entries cropped by LIMIT clause. Ideally
it should ORDER BY DATE(start_date) DESC and then by the ID list. Do I
need some sort of stored function for that?
I.e. the ideal output would be:
+-------+---------------------+
| id | start_date |
+-------+---------------------+
| 109k7 | 2007-10-07 12:06:58 |
| s3x6 | 2007-10-07 08:58:20 |
| wt57 | 2007-10-07 15:57:37 |
| sxmns | 2007-10-06 02:17:30 |
+-------+---------------------+
Thanks
PaPa
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