Thanks for answering
"search character by character" 11 May 2002
Making use of a HTML textfield which sends text to
variable 'varLastName'.
How do I concatenate the variable part('varLastName')
with
the % part is it something like:
SELECT LASTNAME, FIRSTNAME,
DEPARTMENT FROM EMPLOYEES WHERE LASTNAME LIKE
'varLastName'&%
OR is it something like 'varLastName%' ??
Previous Answer:
Use a SQL pattern and the LIKE operator. For example
"C%"
matches any value beginning with "C". "Wil%" matches
any value beginning with "Wil".
Some of the other responses you've gotten indicate
that
you should use "%var%", but that will match values
that
contain var anywhere, not just at the beginning.
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