> >Thanks for answering > >"search character by character" 11 May 2002
> >Making use of a HTML textfield which sends text to > >variable 'varLastName'. > >How do I concatenate the variable > part('varLastName') > >with > >the % part is it something like: > > > >SELECT LASTNAME, FIRSTNAME, > >DEPARTMENT FROM EMPLOYEES WHERE LASTNAME LIKE > >'varLastName'&% > >OR is it something like 'varLastName%' ?? > > Depends on your scripting language, and you haven't > mentioned what that is. I'm making use of ASP and JScript > >Previous Answer: > >Use a SQL pattern and the LIKE operator. For > example > >"C%" > >matches any value beginning with "C". "Wil%" > matches > >any value beginning with "Wil". > > > >Some of the other responses you've gotten indicate > >that > >you should use "%var%", but that will match values > >that > >contain var anywhere, not just at the beginning. > __________________________________________________ Do You Yahoo!? LAUNCH - Your Yahoo! Music Experience http://launch.yahoo.com --------------------------------------------------------------------- Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail <[EMAIL PROTECTED]> To unsubscribe, e-mail <[EMAIL PROTECTED]> Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php