SELECT ip_address, url, count(distinct ip_address) FROM tablename GROUP BY ip_address, url
At 09:48 PM 10/21/2003, John Kelly wrote:
: > -----Original Message----- : > From: John Kelly [mailto:[EMAIL PROTECTED] : > Sent: Tuesday, October 21, 2003 3:45 PM : > To: [EMAIL PROTECTED] : > Cc: [EMAIL PROTECTED] : > Subject: Re: Need help constructing query ... : > : > : > ----- Original Message ----- : > From: "Daniel Clark" <[EMAIL PROTECTED]> : > To: <[EMAIL PROTECTED]> : > Cc: <[EMAIL PROTECTED]> : > Sent: Tuesday, October 21, 2003 2:33 PM : > Subject: Re: Need help constructing query ... : > : > : > : > Hi, I have a table full of logged urls and ip addresses. : > The following : > : > query returns all the urls and the number of requests. How would I : > : > modify it to return unique requests based on distinct ip : > addresses? : > : > : > : > select url, count(*) as pageviews from table group by url order by : > : > pageviews desc : > : : > : How about: : > : : > : SELECT ip_address, url, count(*) : > : FROM tablename : > : GROUP BY ip_adress, url : > : : > Thanks but I could not get that to work. It does not appear : > to count the number of page requests by distinct IPs anyway : > does it? Don't you need something like a : > count(distinct(ip_address)) somewhere in there? : > : > --
----- Original Message ----- From: "Kevin Fries" <[EMAIL PROTECTED]> To: "'John Kelly'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Tuesday, October 21, 2003 3:57 PM Subject: RE: Need help constructing query ...
: Then I think you want : SELECT url, COUNT(DISTINCT ip_address) : FROM tablename : GROUP BY url;
Thanks, this must be a resource intensive query as it works in a few seconds on
a small table but takes 6+ minutes when done on a table with just 100,000
records. Anyway, thanks again.
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Patrick J. Shoaf, Systems Engineer <mailto:[EMAIL PROTECTED]>[EMAIL PROTECTED]
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