On 4/8/04 9:18 AM, "Barry ." <[EMAIL PROTECTED]> wrote: > Hi > > I recently began to work through the Book entitled PHP & MySQL For Dummies > and i am currently stuck towards the end of the forth chapter ive done > everything as said so in the book but i keep getting an error message. Here > is an outline of the problem: > > i have 2 tables one pet containing petName and petType other table is color > containgin petName and petColor. The code which i keep getting errors on is: > > Select * from pet outer join color using (pet.petName=petcolor.petName) ; > > Now Ive posted my problem on several forums on the internet and have a wide > range to replys suggesting what to do but nothing seems to work. > > Can anyone please help me?? > > Barry Smith > > _________________________________________________________________ > Find a cheaper internet access deal - choose one to suit you. > http://www.msn.co.uk/internetaccess >
I think the reason that's not working is because that doesn't look like MySQL syntax for a join statement. From the MySQL documentation, try this: SELECT * FROM pet OUTER JOIN color ON pet.petName=petColor,petName; Keep in mind this will only return rows in pet that have corresponding rows in color. I hope that's what you're looking for. The above code is not tested, but that's the proper JOIN syntax in MySQL. Going through the documentation, I donšt see a USING keyword anywhere. That looks suspiciously like Oracle code. Hope that help! -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
