oops,
for(int i = 1; i < match.length() && !result; i++) result = ismatch(filename, match.substr(1));
 
should be
for(int i = 0; i < filename.length()-match.length() && !result; i++) result = ismatch(filename.substr(i), match.substr(1));
 
guess its friday...
 
Devan
 
On 5/20/05, Devan Lippman <[EMAIL PROTECTED]> wrote:
write a function ismatch() that will take two strings and compare them recursivly with wildcard support.  so for example a call could look like this:
ismatch("Giana 01.adf", "Giana*.adf")
which would call itself
ismatch("iana 01.adf", "iana*.adf")
ismatch("ana 01.adf", "ana*.adf")
...
ismatch(" 01.adf", "*.adf")
and then at the wildcard call
ismatch(" 01.adf", ".adf")
ismatch("01.adf", ".adf")
ismatch("1.adf", ".adf")
ismatch(".adf", ".adf")

something like this:
bool ismatch(string filename, string match)
{
  bool result = false;
  if(match[0] == '*')
  {
    for(int i = 1; i < match.length() && !result; i++) result = ismatch(filename, match.substr(1));
    if(match.length() == 1) return true;
    return result;
  }
  if(match.length() == 1 && match == filename) return true;
  return match[0] == filename[0] && ismatch(filename.substr(1), match.substr(1));
}
 
actually thats horrible, but it probably work it you convert it from my made up language to C++.
 
Devan


On 5/20/05, Jeff <[EMAIL PROTECTED]> wrote:
> On 5/20/05, Jochen K�hner <[EMAIL PROTECTED]> wrote:
>
> >         QFileInfo Info(* it.current());
> >
> >             {
> >
> >                 for (QStringList::Iterator i = rom_extensions.begin(); i !=
> > rom_extensions.end();
> >
> >                 {
> >
> >                     if(Info.extension(false).lower() == *i)
> >
> >                     {
> >
> >                         GameName = Info.baseName(false);
> >
> >                         bRomFound = true;
> >
> >                         break;
> >
> >                     }
> >
> >                 }
> >
> >             }
> >
> >
> > This procedure get all the amiga disk images. But the Problem is, that I
> > need only one if the File name is for Exampe: "Giana 01.adf" "Giana 02.adf"
> > "Giana 03.adf" or "Summer1.adf" "Summer2.adf".
> >
> >
> >
> > I need one filename (as best without the number) and a counter how many
> > files ther are
> >
> > Like: fnm = "Giana 0" , counter = 3   Fnm="Summer" counter = 2
> >
> >
>
> Here is a solution, its not difficult but its not easy.
>
> If all the files have names of the format
>   <game name><optional whitespace><numerics>.adf
> Then you need to have a variable outside the loop which you initialize
> to null that tracks the current <game name>.
>
> Inside the loop where you get a file name you scan it from the end
> backwards starting with the character preceeding ".adf" until you find a
> non-numeric, non-whitespace character. This is the end of the game name.
>
> If the string you have matches the current game name then you increment
> the count of the # of files for this game. If it doesn't then you know
> you've found
> all the files for the current game and you record it.
>
> Then you set the current game name to the new one, the file count to 1 and get
> the next filename.
>
> All of this could be embedded in a method which returns the next game name
> and the # of files it consists of. This would need to be in a class
> which contains
> the file pointer and storage for the current game name field. The current game
> name field holds the next game name which will be processed when the file
> is read. This would be null for the 1st invocation after the file is
> opened. There
> probably has to be an EOF indicator in the class as well.
> _______________________________________________
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>


--
Thanks,
Devan Lippman < [EMAIL PROTECTED]>
 



--
Thanks,
Devan Lippman <[EMAIL PROTECTED]>
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