On Monday, February 17, 2014 11:38:46 AM UTC-6, Fabio Battaglia wrote:

> I don't have 1K/1.2K SIP-10 resistors, but I do have enough 1.5K, do you 
> think those would be OK too?
>

I obtained a copy of the Wilcox book to go with my 68000 board build and 
this kind of thing is discussed at length (pages and pages of equations) 
early in the book, from memory less than 500 ohms could hit the overcurrent 
limit for his design and more than 8500 ohms would undercurrent as a pullup 
depending how thirsty the inputs were for current.  Lower switches faster 
but wastes power, higher uses less power but switches slower. 

I ran the numbers myself using a real live Motorola 74LS682 datasheet and 
you've got two criteria:

1) Too low of a resistance to Vcc and a TTL L output will overcurrent and 
catch fire.
So figure the data sheet Vol = 0.5V and Vcc at 5 V, thats 4.5 volts across 
the resistor.  And the 74LS682 (or most any LS) will catch fire around 24 
mA so 4.5V/0.024A = 187 so less than 190 ohms to Vcc could burn out a LS 
output.  Thats assuming there's no load on the TTL output other than the 
resistor, which would be pretty pointless.  So I'd keep it WELL above 200 
ohms.

2) Too high a resistance to Vcc and the input current of 0.4 mA will pull a 
false low.  So figure 5 volts Vcc, half a volt for ground bounce and half a 
volt for noise, that leaves 4 volts, then Vih for 74LS is 2.0 volts, so the 
resistor must drop less than 4-2 = 2 volts.  At the previously defined 0.4 
mA.  So 2/.0004 = 5000 ohms.  Thats assuming it only drives one input.  So 
I'd keep it well under 5000 ohms.

So, well over 190 ohms and well under 5000 ohms.  How bout a geometric 
mean?  (5000*190)**0.5 = 975 ohms so ideally it would be around 1K which is 
probably where the designers are getting 1K from.

How bad is 1.5 K?  Well, lets get a percentage of the range, from at the 
low end where it catches fire and the high end where it eternally outputs a 
false Low level. and call that full range 100%.  That 1500 ohm pack is 
(1500-975)/(5000-190) = about 11 percent high of center of the safe range.  
Now you were probably building stuff with 10% tolerance resistors so the 
range of plus or minus 5 percent higher or lower means the possible ranges 
just barely don't overlap by about a percent, so there should be a 
measurable effect.

But will the measurable effect matter?  Well, worst case is your 10% 
resistor could be 5% high (or 5% low, which doesn't matter) and you've 
decided to use something that centers 11% high, for a theoretical peak of 
16% high of perfectly centered on a 100% scale.  16 outta 100 is a long, 
long way to go until it fails in eternal false L level.  So you're all 
good, by far.

What if you got the idea of throwing two 1500 resistor packs in parallel?  
Well that would be 750 ohms.  (750-975)/(5000-190) is 5 percent low, so its 
technically better, however, look at the failure mode... Too low means it 
burns out permanently, but too high doesn't hurt anything.  So you're 
closer to parallel two, but in a dangerous direction, and further away but 
in a safer direction to just use one.  Combined with two of them costing 
twice as much, I'm thinking, don't parallel them.  Also the component you 
never install can never fail or have a soldering issue or add to capacitive 
load, so its twice as reliable, sorta, not to install parallel resistors.

TLDR don't worry about 1500 ohms, on the other hand, I wouldn't go trying 
4700 ohm packs..

-- 
You received this message because you are subscribed to the Google Groups 
"N8VEM-S100" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
For more options, visit https://groups.google.com/groups/opt_out.

Reply via email to