The following two lines would give the sum of a number with any
number of digits
num=1123456789;
while(num && (sum+=num%10, num/=10));
--- In [EMAIL PROTECTED], zulqrnain alisial
<[EMAIL PROTECTED]> wrote:
> try this in C++ main()
> int sum=0
> for (int i=1;i<=10;i++)
> {
> sum+=i;
> }
> cout<<sum;
>
>
> surya battina <[EMAIL PROTECTED]> wrote:
> hi all
>
> can u give the idea to sum all digits of a 10 or more
digited number using single statement.
>
>
>
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