i goot this code but one of u plz modify print only
at last
#include<stdio.h.
main()
{
int num=123,sum=0;
for(;num;sum+=num%10,num/=10,printf("\nSUM=%d",sum));
}
--- surya battina <[EMAIL PROTECTED]> wrote:
> hi
>
> u r mistaken my question.now i will
> explain u clearly.
> if a number s=12345678933
> then i have to count
> 1+2+3+4+5+6+7+8+9+3+3
>
> and this should be done in a sigle
> statement if u sue for loop there is 3 statements u
> have so it is not worked.
>
>
>
>
> zulqrnain alisial <[EMAIL PROTECTED]> wrote:
> try this in C++ main()
> int sum=0
> for (int i=1;i<=10;i++)
> {
> sum+=i;
> }
> cout<<sum;
>
>
> surya battina <[EMAIL PROTECTED]> wrote:
> hi all
>
> can u give the idea to sum all digits of a
> 10 or more digited number using single statement.
>
>
>
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