Probably the easiest way is to use the *0.. variable length path notation
(0 or more); also, it's a good idea to put arrows in your queries:
MATCH (n:Variant { name:'variant2'
})<-[:UPDATED_VARIANT*0..]-(v)--(a:Allele)
RETURN n,v,a
In cases where no :UPDATED_VARIANT relationship exists, n and v will be the
same node.
Wes
On Tue, Jan 21, 2014 at 12:38 PM, Alex Frieden <[email protected]> wrote:
> Hi all, I have this graph. http://console.neo4j.org/r/2yadry (let me
> know if that doesn't work)
> create
> (_6:Allele {name:"allele1"}),
> (_7:Variant {name:"variant1"}),
> (_8:Variant {name:"variant2"}),
> _6-[:HAS_VARIANT]->_7,
> _7-[:UPDATED_VARIANT]->_8
>
> I want to be able to get the allele from any variant on the chain. So
> this works:
>
> MATCH (n:Variant {name:'variant2'})-[:UPDATED_VARIANT]-(v)--(a:Allele)
> RETURN n,v,a;
>
> however, if I don't want to start with the last one in the chain, it
> doesn't work.
>
> How can I modify this so it returns the allele for any variant on the
> chain. Thanks!
>
>
>
>
>
>
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