Thanks Wes worked perfectly!
On Jan 21, 2014 12:44 PM, "Wes Freeman" <[email protected]> wrote:
> Probably the easiest way is to use the *0.. variable length path notation
> (0 or more); also, it's a good idea to put arrows in your queries:
>
> MATCH (n:Variant { name:'variant2'
> })<-[:UPDATED_VARIANT*0..]-(v)--(a:Allele)
> RETURN n,v,a
>
> In cases where no :UPDATED_VARIANT relationship exists, n and v will be
> the same node.
>
> Wes
>
> On Tue, Jan 21, 2014 at 12:38 PM, Alex Frieden <[email protected]> wrote:
>
>> Hi all, I have this graph. http://console.neo4j.org/r/2yadry (let me
>> know if that doesn't work)
>> create
>> (_6:Allele {name:"allele1"}),
>> (_7:Variant {name:"variant1"}),
>> (_8:Variant {name:"variant2"}),
>> _6-[:HAS_VARIANT]->_7,
>> _7-[:UPDATED_VARIANT]->_8
>>
>> I want to be able to get the allele from any variant on the chain. So
>> this works:
>>
>> MATCH (n:Variant {name:'variant2'})-[:UPDATED_VARIANT]-(v)--(a:Allele)
>> RETURN n,v,a;
>>
>> however, if I don't want to start with the last one in the chain, it
>> doesn't work.
>>
>> How can I modify this so it returns the allele for any variant on the
>> chain. Thanks!
>>
>>
>>
>>
>>
>>
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