Can i have an full example on this
On Saturday, July 19, 2014 8:45:15 PM UTC+5:30, Michael Hunger wrote:
>
> basically
>
> Node pizza =
> gdb.findByLabelAndProperty("Thing","name","Pizza").iterator().next();
> Node iceCream = gdb.findByLabelAndProperty("Thing","name","Ice
> Cream").iterator().next();
>
> for (Relationship rel : pizza.getRelationships(Direction.INCOMING,
> Type.LIKES) {
> Node person = rel.getStartNode();
> if (connected(person,iceCream,Type.LIKES) result.add(person);
> }
>
> public boolean connected(Node from, Node to, RelationshipType type) {
> for (Relationship rel : from.getRelationships(Direction.OUTGOING, type) {
> if (rel.getEndNode().equals(to)) return true;
> }
> return false;
> }
>
> 2) you can also collect person-nodes from both like's into a Set each and
> then use set1.retailAll(set2)
> 3) you can also iterate over all people and check if the end-nodes of
> their likes relationships are pizza AND ice-cream and if both then add them
> to the result
>
> Am 18.07.2014 um 14:07 schrieb ems eril <[email protected] <javascript:>>:
>
> Hi ,
>
> Im very new to Ne4j , I have the following model depicted in the digram
> attached to this message . I like to know how I can get all persons who
> like both pizza and ice cream using the JAVA API . I know how to do this in
> cypher but the traversal API is a bit getting use to and Im not sure how I
> can say using the API give me all person nodes who like both pizza and ice
> cream.
>
> Thanks in advance
>
> -ems
>
>
> <https://lh6.googleusercontent.com/-yhndFA-bvgY/U8mMUxvdyJI/AAAAAAAAABg/SF5fCQsKnSQ/s1600/simple_model.jpg>
>
>
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