What are you missing? Perhaps you should try with this and come back with
concrete questions?

Cheers, Michael


On Wed, Aug 6, 2014 at 10:44 AM, Amrutha Valli <[email protected]>
wrote:

> Can i have an full  example  on this
>
>
> On Saturday, July 19, 2014 8:45:15 PM UTC+5:30, Michael Hunger wrote:
>
>> basically
>>
>> Node pizza = gdb.findByLabelAndProperty("Thing","name","Pizza").
>> iterator().next();
>> Node iceCream = gdb.findByLabelAndProperty("Thing","name","Ice
>> Cream").iterator().next();
>>
>> for (Relationship rel : pizza.getRelationships(Direction.INCOMING,
>> Type.LIKES) {
>>     Node person = rel.getStartNode();
>>     if (connected(person,iceCream,Type.LIKES) result.add(person);
>> }
>>
>> public boolean connected(Node from, Node to, RelationshipType type) {
>>   for (Relationship rel : from.getRelationships(Direction.OUTGOING,
>> type) {
>>     if (rel.getEndNode().equals(to)) return true;
>>   }
>>   return false;
>> }
>>
>> 2) you can also collect person-nodes from both like's into a Set each and
>> then use set1.retailAll(set2)
>> 3) you can also iterate over all people and check if the end-nodes of
>> their likes relationships are pizza AND ice-cream and if both then add them
>> to the result
>>
>> Am 18.07.2014 um 14:07 schrieb ems eril <[email protected]>:
>>
>> Hi ,
>>
>>    Im very new to Ne4j , I have the following model depicted in the
>> digram attached to this message . I like to know how I can get all persons
>> who like both pizza and ice cream using the JAVA API . I know how to do
>> this in cypher but the traversal API is a bit getting use to and Im not
>> sure how I can say using the API give me all person nodes who like both
>> pizza and ice cream.
>>
>> Thanks in advance
>>
>> -ems
>>
>>
>> <https://lh6.googleusercontent.com/-yhndFA-bvgY/U8mMUxvdyJI/AAAAAAAAABg/SF5fCQsKnSQ/s1600/simple_model.jpg>
>>
>>
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