There is currently a built-in default limit of 15 steps, which you can extend
like this:
> MATCH p=shortestPath( ( c:Class {name:"bar"} )-[:PARENT*..20]->(
> p:Class{name:"default"} ) )
> RETURN p
> Am 29.06.2015 um 21:50 schrieb Krishna Marri <[email protected]>:
>
> Hello,
>
> I am using Neo4j 2.2.2 on Mac OS X 10.10.2
>
> I have a chain of nodes as follows -
>
> ( Class{name: bar} ) --- [ PARENT ] ----> ( Class(name: foo) ) --- [ PARENT
> ] ---> ( Class ) ............... --- [ PARENT ] ---> ( Class(name: default) )
>
> When I run this query -
> MATCH p=( ( c:Class {name:"bar"} )-[:PARENT*]->( p:Class{name:"default"} ) )
> RETURN p
>
> I am getting a single path of length 18, which is right
>
> but when I run the same query with shortest path -
> MATCH p=shortestPath( ( c:Class {name:"bar"} )-[:PARENT*]->(
> p:Class{name:"default"} ) )
> RETURN p
>
> I am not getting any path, shouldn't it return the one existing path
>
>
>
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