Please mention this in the documentation, I had been googling this for 2
days with no avail.
Thanks for the prompt answer.
On Monday, June 29, 2015 at 1:09:46 PM UTC-7, Michael Hunger wrote:
>
> There is currently a built-in default limit of 15 steps, which you can
> extend like this:
>
>
> MATCH p=shortestPath( ( c:Class {name:"bar"} )-[:PARENT*..20]->(
> p:Class{name:"default"} ) )
> RETURN p
>
>
>
> Am 29.06.2015 um 21:50 schrieb Krishna Marri <[email protected]
> <javascript:>>:
>
> Hello,
>
> I am using Neo4j 2.2.2 on Mac OS X 10.10.2
>
> I have a chain of nodes as follows -
>
> ( Class{name: bar} ) --- [ PARENT ] ----> ( Class(name: foo) ) --- [
> PARENT ] ---> ( Class ) ............... --- [ PARENT ] ---> ( Class(name:
> default) )
>
> When I run this query -
> MATCH p=( ( c:Class {name:"bar"} )-[:PARENT*]->( p:Class{name:"default"} )
> )
> RETURN p
>
> I am getting a single path of length 18, which is right
>
> but when I run the same query with shortest path -
> MATCH p=shortestPath( ( c:Class {name:"bar"} )-[:PARENT*]->(
> p:Class{name:"default"} ) )
> RETURN p
>
> I am not getting any path, shouldn't it return the one existing path
>
>
>
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