1. you probably don't need bi-directional relationships, one is good enough.

2. one way to get the subgraphs is to get one node of each sub-graph and
return all paths for that node up to a certain length.

MATCH (n:Node) where n.name IN ["foo", "bar"]
MATCH path = (n)-[*..5]-()
UNWIND nodes(path) as node
RETURN n, collect(distinct node) as nodes

3. you can also use the path-expand
<https://neo4j-contrib.github.io/neo4j-apoc-procedures/#_graph_algorithms>
and clustering algorithms in the APOC procedure library

On Tue, Apr 11, 2017 at 11:17 AM, Kai Wang <[email protected]> wrote:

> Hi,all,
>
> I'm using neo4j and I build a large graph that has a lot of subgraph. For
> example, in the pic below there are 4 subgraphs. How can I get 4 groups
> of nodes by cypher query? I mean  it can return [node1, node2, node3],
> [node4, node5], [node6, node7, node8] ,each list represent a subgraph.
>
>
> <https://lh3.googleusercontent.com/-YcXm2szn3mw/WOyef6pE-vI/AAAAAAAAAA8/TVB1mWQzJY0sSuLfkwjb6JbEQoDq06Z3gCLcB/s1600/%25E5%2590%258C%25E4%25B9%2589%25E8%25AF%258D%25E7%25BD%2591%25E7%25BB%259C.PNG>
>
>
>
>
>
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