Thanks. My frustration is that I want to automatically detect all subgraph, 
which means I dont't know how to determine a list of "one node of each 
sub-graph". But using collect in cypher is pretty good hint. I'm also 
concerned about the performance.


在 2017年4月12日星期三 UTC+8上午3:05:41,Michael Hunger写道:
>
> 1. you probably don't need bi-directional relationships, one is good 
> enough.
>
> 2. one way to get the subgraphs is to get one node of each sub-graph and 
> return all paths for that node up to a certain length.
>
> MATCH (n:Node) where n.name IN ["foo", "bar"]
> MATCH path = (n)-[*..5]-()
> UNWIND nodes(path) as node
> RETURN n, collect(distinct node) as nodes
>
> 3. you can also use the path-expand 
> <https://neo4j-contrib.github.io/neo4j-apoc-procedures/#_graph_algorithms> 
> and clustering algorithms in the APOC procedure library
>
> On Tue, Apr 11, 2017 at 11:17 AM, Kai Wang <[email protected] 
> <javascript:>> wrote:
>
>> Hi,all,
>>
>> I'm using neo4j and I build a large graph that has a lot of subgraph. For 
>> example, in the pic below there are 4 subgraphs. How can I get 4 groups 
>> of nodes by cypher query? I mean  it can return [node1, node2, node3], 
>> [node4, node5], [node6, node7, node8] ,each list represent a subgraph.
>>
>>
>> <https://lh3.googleusercontent.com/-YcXm2szn3mw/WOyef6pE-vI/AAAAAAAAAA8/TVB1mWQzJY0sSuLfkwjb6JbEQoDq06Z3gCLcB/s1600/%25E5%2590%258C%25E4%25B9%2589%25E8%25AF%258D%25E7%25BD%2591%25E7%25BB%259C.PNG>
>>
>>
>>
>>
>>
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