On 10/11/10 8:46 AM, Steve wrote:
Hi All,
So I then thought (from my reading of 101 textbooks!); the current is
equal for the entire circuit, I know the resistor, so if I measure the
voltage drop across the resistor I can use I=V/R to calculate the
current, where I am plugging in the voltage drop across the resistor
and the resistor value into V and R.
Is that a correctly thought through approach, or am I making a silly
newbie mistake?
Steve, welcome to the wonderful world of Nixies!
You have done this the right way. For a newbie, you're getting the hang
of this quickly.
--
David Forbes, Tucson AZ
http://www.cathodecorner.com/
--
You received this message because you are subscribed to the Google Groups
"neonixie-l" group.
To post to this group, send an email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/neonixie-l?hl=en-GB.