You really ought to take the time to at least do a back of the napkin
schematic. :D
I'm trying to decide how this arrangement works out to being more pin
efficient than the standard way. So, you must have 8 GPIO pins delegated
to driving 74141 inputs, and then 3 GPIO pins delegated to the anode
drivers. That is 11 pins.
With a standard 1x6 mux (6 anode drivers, one 74141), we use 10 GPIO pins.
Until you show us exactly what you've got going on, we're going to be of
limited help to you. Also, you'll find that going through the exercise
of drawing out the schematic may help you solve your own design problems. :)
-Adam
On 3/16/2012 1:17 PM, Imbanon wrote:
Blank as in set to 0?
My sequence is pretty much this;
set bits to first mux
set bits to second mux
turn on one anode driver
wait for 3ms
turn off anode driver
blanking period of 200us
repeat this n-times
I don't really touch muxes' bits when I am not displaying anything
(nixies turned off). I only set them again when I want to display time
again.
On Mar 16, 9:09 pm, Adam Jacobs<[email protected]> wrote:
Right, each anode driver powers 2 nixies. You need to be careful to have
one of the pair's K155ID1's set to blank at any given time, though.
Never sink more than one of the K155ID1's at any given time and this
arrangement will work fine.
-Adam
On 3/16/2012 1:06 PM, Imbanon wrote:
I think my post was a bit unclear. I AM turning on two at the time x)
I have 3 pins controlling 6 nixies. That means one pin turns on 2
nixies at the same time. Each lit nixie is controlled by separate
K155ID1 (two muxes in total).
Or am I having problems understanding you..
Cheers
On Mar 16, 9:00 pm, Adam Jacobs<[email protected]> wrote:
You could do this.. It's not ideal in my opinion, but as long as you are
careful to never turn on more than one of the paired nixies at a time,
you could get away with multiplexing this way. I would set the anode
resistor at something like 10-15k to start with.
I think that this looks like a great reason to learn how shift registers
work, though. :)
-Adam
On 3/16/2012 12:56 PM, Imbanon wrote:
Actually that is exactly what I am doing. I have 3 anode control
circuits, each controlling 2 nixies. I am doing this because I lack
digital I/O pins. Should I then change my design to one anode resistor
per tube? I would still have only 3 anode drivers..
On Mar 16, 8:40 pm, John Rehwinkel<[email protected]> wrote:
And I have to clear out that I have a common anode resistor for 2
tubes, making a total of 3 anode resistors for all 6 tubes.
It seems to me that would only work if you only selected a cathode for one tube
at a time. Otherwise (if you tried to light both tubes at once), only one tube
would light, pulling the
anode end of the resistor down to the maintaining voltage, which would be
insufficient
to light the second tube (because it is now below the striking voltage).
- John
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