Right, each anode driver powers 2 nixies. You need to be careful to have
one of the pair's K155ID1's set to blank at any given time, though.
Never sink more than one of the K155ID1's at any given time and this
arrangement will work fine.
-Adam
On 3/16/2012 1:06 PM, Imbanon wrote:
I think my post was a bit unclear. I AM turning on two at the time x)
I have 3 pins controlling 6 nixies. That means one pin turns on 2
nixies at the same time. Each lit nixie is controlled by separate
K155ID1 (two muxes in total).
Or am I having problems understanding you..
Cheers
On Mar 16, 9:00 pm, Adam Jacobs<[email protected]> wrote:
You could do this.. It's not ideal in my opinion, but as long as you are
careful to never turn on more than one of the paired nixies at a time,
you could get away with multiplexing this way. I would set the anode
resistor at something like 10-15k to start with.
I think that this looks like a great reason to learn how shift registers
work, though. :)
-Adam
On 3/16/2012 12:56 PM, Imbanon wrote:
Actually that is exactly what I am doing. I have 3 anode control
circuits, each controlling 2 nixies. I am doing this because I lack
digital I/O pins. Should I then change my design to one anode resistor
per tube? I would still have only 3 anode drivers..
On Mar 16, 8:40 pm, John Rehwinkel<[email protected]> wrote:
And I have to clear out that I have a common anode resistor for 2
tubes, making a total of 3 anode resistors for all 6 tubes.
It seems to me that would only work if you only selected a cathode for one tube
at a time. Otherwise (if you tried to light both tubes at once), only one tube
would light, pulling the
anode end of the resistor down to the maintaining voltage, which would be
insufficient
to light the second tube (because it is now below the striking voltage).
- John
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