From: Jason Baron
> Sent: 19 September 2016 19:34
> sizeof(struct bnx2x_mcast_list_elem) = 24. So there are 170 per
> page on x86. So if we want to fit 2,048 elements, we need 12 pages.

If you only need to save the mcast addresses you could use a 'heap'
that requires no overhead per entry and gives you O(log) lookup.
6 bytes per entry is 682 in a 4k page.


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