You can create one buffer and then use to send to all your sockets the very 
same buffer content but using different indexes (read here) using the 
ByteBuf.duplicate() method.

https://netty.io/4.1/api/io/netty/buffer/ByteBuf.html#duplicate--

Javadoc says:


public abstract ByteBuf <https://netty.io/4.1/api/io/netty/buffer/ByteBuf.html> 
duplicate()

Returns a buffer which shares the whole region of this buffer. Modifying 
the content of the returned buffer or this buffer affects each other's 
content while they maintain separate indexes and marks. This method does 
not modify readerIndex or writerIndex of this buffer.

The reader and writer marks will not be duplicated. Also be aware that this 
method will NOT call retain() 
<https://netty.io/4.1/api/io/netty/buffer/ByteBuf.html#retain--> and so the 
reference count will NOT be increased.
Returns:A buffer whose readable content is equivalent to the buffer 
returned by slice() 
<https://netty.io/4.1/api/io/netty/buffer/ByteBuf.html#slice-->. However 
this buffer will share the capacity of the underlying buffer, and therefore 
allows access to all of the underlying content if necessary.

Le vendredi 12 avril 2019 06:31:57 UTC+2, [email protected] a écrit :
>
> Are there any optimizations available if I'd like to send the very same 
> data to dozens (or hundreds) of Websocket channels?
> At a minimum I'd like to avoid creating (and copying) the data to new 
> buffers. Ideally I would provide a single buffer and a list of channels.
>

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