Yes exactly like this > Am 12.04.2019 um 08:19 schrieb Frederic <[email protected]>: > > You can create one buffer and then use to send to all your sockets the very > same buffer content but using different indexes (read here) using the > ByteBuf.duplicate() method. > > https://netty.io/4.1/api/io/netty/buffer/ByteBuf.html#duplicate-- > > Javadoc says: > > public abstract ByteBuf duplicate() > Returns a buffer which shares the whole region of this buffer. Modifying the > content of the returned buffer or this buffer affects each other's content > while they maintain separate indexes and marks. This method does not modify > readerIndex or writerIndex of this buffer. > The reader and writer marks will not be duplicated. Also be aware that this > method will NOT call retain() and so the reference count will NOT be > increased. > > Returns: > A buffer whose readable content is equivalent to the buffer returned by > slice(). However this buffer will share the capacity of the underlying > buffer, and therefore allows access to all of the underlying content if > necessary. > > Le vendredi 12 avril 2019 06:31:57 UTC+2, [email protected] a écrit : >> >> Are there any optimizations available if I'd like to send the very same data >> to dozens (or hundreds) of Websocket channels? >> At a minimum I'd like to avoid creating (and copying) the data to new >> buffers. Ideally I would provide a single buffer and a list of channels. > > -- > You received this message because you are subscribed to the Google Groups > "Netty discussions" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > https://groups.google.com/d/msgid/netty/4c93f31c-a1f0-48be-94ef-b7cda094e2c5%40googlegroups.com. > For more options, visit https://groups.google.com/d/optout.
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