Thanks for the reply.

However, this is the same answer as what I keep coming across that doesn't 
really answer my question.  What is the downside?  I want to see a real-world 
example of what happens when I don't follow this contract. I've yet to see an 
example of something bad happening in this situation.  I'm sure I'm wrong, but 
I need to know *why*.

When would someone ever call:

   getSomething(args, cb);

... and then assume they can call something else in the meantime?


Thanks,

Bryan


On Aug 21, 2013, at 12:32 AM, Floby <[email protected]> wrote:

> Same as above.
> A "callback" is meant to be called back after some operations are made. In 
> node, that means they're probably gonna get called when the current stack has 
> unwound. If you called the callback synchronously, that means it behaves 
> differently.
> process.nextTick un most cases execute the given function immediately after 
> the current stack ends (with some limitations for recursivity) so it's not 
> really a performance killer.
> 
> Doing so helps you respect your function/method contract :)
> 
> Saying that "in most case, it's not needed" is too big of an assumption of 
> what your user is doing with your code. IMO.
> 
> 
> On Tuesday, 20 August 2013 19:47:22 UTC+2, Bryan Donovan wrote:
> I have been writing node.js client code for a couple of years now, and have 
> authored a couple open source libraries, but somehow I missed the memo 
> telling me that I'm supposed to wrap 'synchrounous' callbacks in 
> process.nextTick().  I kind-of understand why that is a best-practice, but 
> what I don't understand is what the drawback is if you don't do it.
> 
> For example, I write code like this all the time, and have never had a single 
> problem with it:
> 
> function getSomething(args, cb) {
>     if (!args) { return cb(new Error('args required')); }
>     if (!args.id) { return cb(new Error('args.id required')); }
> 
>     SomeDatabase.get({id: args.id}, cb);
> }
> 
> What are the potential issues with not wrapping those arg checks in 
> process.nextTick()?
> 
> 
> Thanks, 
> 
> Bryan
> 
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