Hi, Tim.
You write
I want to spawn a child process and have *all* output go to the same file.
>
>
Why? (looking down the thred...)
I'm spawning long running tasks, which may outlive the process that spawned
> them (which is why I'm directing the output into a file).
>
Fine.
It is right there in docs: "Example of detaching a long-running process and
redirecting its output to a file"
Like you've found:
> So I guess I have to explicitly truncate the file first, then open two
> append streams to it?
>
> //fs.closeSync(fs.openSync('/tmp/output.log', 'w'));
> var output = fs.openSync('/tmp/output.log', 'a');
> var output2 = fs.openSync('/tmp/output.log', 'a');
> childProcess.spawn('bash', ['-c', 'echo STOUT; echo STDERR >&2; echo
> DONE;'], {stdio: ['ignore', output, output2]});
>
>
Works on both MS Windows and */Linux (tested). It even looks symmetrical
(by action, not by value, but anyway)
Thus, why not to just read docs and use it, instead of remembering all that
legacy tricks on other languages, platforms, etc.?
BTW, this works on MS Windows without overlapping: {stdio: ['ignore',
output, output]}...
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