Hi,
On Sun, Aug 31, 2025 at 12:08 PM Fabrice Couvreur
<fabrice1.couvr...@gmail.com> wrote:
>
> Hi,
> In the example below, the formula number is not located on the baseline of
> the last equality. How can I make this happen ?
> Thanks for your help.
> Fabrice
>
>
> \starttext
> \startplaceformula
> \startformula
> \startalign
> \NC f(x) \EQ a\left(x²+\frac{b}{a}x\right)+c\NR
> \NC \EQ
> a\left(\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a²}\right)+c\NR
> \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+c\NR
> \NC \EQ
> a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+\frac{4ac}{4a}\NR
> \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²-4ac}{4a}\NR
> \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{\Delta}{4a}\NR
> \stopalign
> \stopformula
> \stopplaceformula
> \stoptext
Add it to the last \NR:
\starttext
\startplaceformula
\startformula
\startalign
\NC f(x) \EQ a\left(x²+\frac{b}{a}x\right)+c\NR
\NC \EQ
a\left(\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a²}\right)+c\NR
\NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+c\NR
\NC \EQ
a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+\frac{4ac}{4a}\NR
\NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²-4ac}{4a}\NR
\NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{\Delta}{4a}\NR[eq:foo]
\stopalign
\stopformula
\stopplaceformula
\stoptext
/Mikael
___________________________________________________________________________________
If your question is of interest to others as well, please add an entry to the
Wiki!
maillist : ntg-context@ntg.nl /
https://mailman.ntg.nl/mailman3/lists/ntg-context.ntg.nl
webpage : https://www.pragma-ade.nl / https://context.aanhet.net (mirror)
archive : https://github.com/contextgarden/context
wiki : https://wiki.contextgarden.net
___________________________________________________________________________________
