Hi Mikael,
Thanks for your reply, and I'm not against a touch of modernity !
Fabrice
Le dim. 31 août 2025 à 12:46, Mikael Sundqvist <mic...@gmail.com> a écrit :
> Hi,
>
> or, if you prefer to "be modern", you can try
>
> \startformula
> f(x)
> \alignhere = a\left(x²+\frac{b}{a}x\right)+c
> \breakhere = a\left(\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a²}\right)+c
> \breakhere = a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+c
> \breakhere = a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+\frac{4ac}{4a}
> \breakhere = a\left(x+\frac{b}{2a}\right)^2-\frac{b²-4ac}{4a}
> \breakhere = a\left(x+\frac{b}{2a}\right)^2-\frac{\Delta}{4a}
> \numberhere[eq:foo]
> \stopformula
>
> /Mikael
>
> On Sun, Aug 31, 2025 at 12:24 PM Mikael Sundqvist <mic...@gmail.com>
> wrote:
> >
> > Hi,
> >
> > On Sun, Aug 31, 2025 at 12:08 PM Fabrice Couvreur
> > <fabrice1.couvr...@gmail.com> wrote:
> > >
> > > Hi,
> > > In the example below, the formula number is not located on the
> baseline of the last equality. How can I make this happen ?
> > > Thanks for your help.
> > > Fabrice
> > >
> > >
> > > \starttext
> > > \startplaceformula
> > > \startformula
> > > \startalign
> > > \NC f(x) \EQ a\left(x²+\frac{b}{a}x\right)+c\NR
> > > \NC \EQ
> a\left(\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a²}\right)+c\NR
> > > \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+c\NR
> > > \NC \EQ
> a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+\frac{4ac}{4a}\NR
> > > \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²-4ac}{4a}\NR
> > > \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{\Delta}{4a}\NR
> > > \stopalign
> > > \stopformula
> > > \stopplaceformula
> > > \stoptext
> >
> > Add it to the last \NR:
> >
> > \starttext
> > \startplaceformula
> > \startformula
> > \startalign
> > \NC f(x) \EQ a\left(x²+\frac{b}{a}x\right)+c\NR
> > \NC \EQ
> > a\left(\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a²}\right)+c\NR
> > \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+c\NR
> > \NC \EQ
> > a\left(x+\frac{b}{2a}\right)^2-\frac{b²}{4a}+\frac{4ac}{4a}\NR
> > \NC \EQ a\left(x+\frac{b}{2a}\right)^2-\frac{b²-4ac}{4a}\NR
> > \NC \EQ
> a\left(x+\frac{b}{2a}\right)^2-\frac{\Delta}{4a}\NR[eq:foo]
> > \stopalign
> > \stopformula
> > \stopplaceformula
> > \stoptext
> >
> > /Mikael
>
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