Hi John,
>> Wolfgang, thanks - but this does not seem to fix the problem. The
>> "last page" appears opposite page 3 instead of opposite page 1.
>>
>> To be clear, I am looking for a way to specify that content is to be
>> placed on the outside of the cover, i.e. printed on the same side of
>> the same sheet as page 1, when "arranged".
Could you try the following page brake method.
\unprotect
\installpagebreakhandler {newquadruple}%
{\ifdoublesided
\!!counta\realpageno
\!!countb\realpageno
\advance\!!counta 4
\divide\!!counta 4
\multiply\!!counta 4
\advance\!!countb 1
\advance\!!counta-\!!countb
\executepagebreakhandler\v!yes
\dorecurse\!!counta{\executepagebreakhandler\v!empty}%
\fi}
\protect
>> \setuppapersize[A5][A4]
>> \setuparranging[2UP,rotated,doublesided]
>> \setuppagenumbering[alternative=doublesided]
>>
>> \setuplayout[margin=0pt,width=fit]
>> \setupbodyfont[16pt]
>>
>> \starttext
>>
>> \dorecurse{11}{\input tufte \par \input knuth \par}
>>
>> \page[8]
>
> \page[8] is useless in this example because you're already beyound
> the eight page and the argument is useless in this case.
>
> \page[quadruple]
\page[newquadruple]
>> Back Cover
>>
>> \stoptext
>>
>> texexec --arrange --paperformat=a5a4 --printformat=up test2.tex
>
> texexec test2
>
> you need --arrange only for documents with a table of content, indices ...
Wolfgang
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