Hi,
I found a possibly bug (I attached the doc). With bigskip twocolumns
work but with \column it does not. That is, with the diff:
98c98
< \bigskip
---
> %\bigskip
100c100
< %\column
---
> \column
it does not work: the last exercise is shown in the first column.
Can anyone explain me what happens?
Thanks in advance,
Xan.
PS: Please CCme.
\enableregime[utf]
\setupbodyfont [cmr,11pt]
\mainlanguage[ca]
\setuppagenumbering [location={footer}]
\setuppapersize [A4]
\setuplayout[topspace=1.5cm,margin=1.5cm,header=1.5cm,footer=1.5cm,width=fit,height=fit,backspace=1.5cm]
\setuphead[title][align={center},style={\sca}, after={\medskip}]
\setuphead[subject][after={\hrule\medskip}]
% AMSTHM
\defineenumeration
[exercici]
[text={Exercici},headstyle=bold,between=\blank,textdistance=1em,
stopper={.\space},location=serried,left={\bgroup\bf},right={\egroup},width=fit,headstyle=\ss,title=yes,titlestyle=\ss,titledistance=.5em]
% Heads and footers
\setupfootertexts[\pagenumber]
\setupfooter[text][before=\hrule]
\setupheader[text][after=\hrule]
\setupheadertexts[{\tfx \mid IES Binissalem \mid 4t D \mid MAT \mid }][{\tfx Sistemes d'equacions \mid Examen \mid 15/3/2012 \mid}]
% underline
\setupunderbar[alternative=b]
\starttext
\title{Examen de Matemà tiques}
\bigskip
\startframedtext[width=broad, location=middle, before={}]
\startalignment[middle]
Feis l'opció comuna de totes maneres i, després, trieu entre l'Opció A o l'Opció B
\stopalignment
\stopframedtext
\subject{Part comuna}
\startcolumns
\startexercici Resoleu emprant el mètode de substitució:
\placeformula
\startformula
\startmathalignment
\NC x + 3y \NC = 9 \NR[+]
\NC 2x - y \NC = 3 \NR
\stopmathalignment
\stopformula
\stopexercici
\startexercici Resoleu pel mètode de reducció:
\placeformula
\startformula
\startmathalignment
\NC 3x + 7y \NC = -23 \NR[+]
\NC 5x + 4y \NC = -23 \NR
\stopmathalignment
\stopformula
\stopexercici
\stopcolumns
\subject{Opció A}
\startexercici Resoleu pel mètode que vulgueu:
\placeformula
\startformula
\startmathalignment
\NC \frac{x}{3} + \frac{4y}{5} - 3(x+y) \NC = -19 \NR[+]
\NC \frac{3x}{3} - \frac{1}{3} (y-5) \NC = 3 \NR
\stopmathalignment
\stopformula
\stopexercici
\subject{Opció B}
\startcolumns
\startexercici Resoleu aquest sistema pel mètode que vulgueu:
\placeformula
\startformula
\startmathalignment
\NC -2x - y \NC = -11 \NR[+]
\NC 3x - y \NC = 9 \NR
\stopmathalignment
\stopformula
\stopexercici
\bigskip
%\column
\startexercici Resoleu el sistema següent pel mètode que considereu oportú:
\placeformula
\startformula
\startmathalignment
\NC 2x + \frac{5y}{2} \NC = 7 \NR[+]
\NC -3x + y \NC = -1 \NR
\stopmathalignment
\stopformula
\stopexercici
\stopcolumns
\stoptext
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