----- Original Message -----
From: "Ben Scott" <[email protected]>
To: "NT System Admin Issues" <[email protected]>
Sent: Tuesday, January 20, 2009 2:25 PM
Subject: Re: Batch file task
On Tue, Jan 20, 2009 at 1:44 PM, m b <[email protected]> wrote:
I need to create a section of a batch file that will determine whether a
folder has had files added to it or not, and then perform one of two
actions.
If you're just looking to see if the folder is empty or not, this may
help:
DIR /B %folder% | findstr /R . > NUL
That will return success if %folder% is empty, or failure if %folder%
contains anything at all. ("Success" being a zero exit code (error
level), and "failure" being a non-zero exit code.)
If you're actually looking to at directory contents changes, then
yah, you'll need to save previous directory state and compare, like
you spoke of.
the "fc" command doesn't seem to give me any output I can use within the
batch file
??? If my testing, FC.EXE returns success if files are identical,
and failure if they differ. Win XP Pro SP2. Demonstration batch
file:
FC orig.txt same.txt > NUL
@ECHO ERRORLEVEL=%ERRORLEVEL%
FC orig.txt diff.txt > NUL
@ECHO ERRORLEVEL=%ERRORLEVEL%
That produces this output:
Ben>FC orig.txt same.txt 1>NUL
ERRORLEVEL=0
Ben>FC orig.txt diff.txt 1>NUL
ERRORLEVEL=1
-- Ben
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