Hi Howard,

The Axis moves but the Camera is static. What am I missing?



On Sep 12, 2012, at 3:07 PM, Howard Jones wrote:

> I think you mean convert it to use as a camera rather than for the camera 
> tracker, do you? 
> I wrote a tool to do that a few years which I thought I'd put on Nukepedia 
> but must have dreamt it, so attached is a new version.
> I only wrote it as a challenge and used it a couple of times in production so 
> it's probably a bit ropey.
> 
> On creativeCrash at 
> http://www.creativecrash.com/nuke/downloads/gizmos/3d/c/tracker2camera , but 
> I think this version fails with multiviews which is fixed in attached.
> 
> Anyway copy your track into the node and then 'create scene' for static 
> camera moving geo or 'create camera' for moving camera. Place geo at 0. I did 
> try and set up one that allowed pushing back in z but cant remember correct 
> maths unfortunatly.
> 
> Cheers 
> Howard
> p.s. this is the description from Creativecrash...
> 
> 
> tracker2Camera is a quick and dirty 3D tracker. It takes a 2Dtrack, and 
> converts it to the equivalent 3D space and spits out a nodal camera/scene, or 
> translating camera/axis depending on what you want to achieve. This way you 
> can track a point and put in a 3D object. (For xy translate or nodal pans 
> plus rotation only, for crazy moves you'll still need a 3D tracker.)
> 
> 
> From: Marten Blumen <[email protected]>
> To: Nuke user discussion <[email protected]> 
> Sent: Wednesday, 12 September 2012, 21:43
> Subject: Re: [Nuke-users] Can I use 2D track for 3D Camera?
> 
> Use the 'Add User Track' btn in Tracking tab in the CameraTracking node.  
> 
> On 13 September 2012 08:13, Todd Groves <[email protected]> wrote:
> In a shot I'm trying to get a Camera Track for, there is not enough parallax 
> for the Cam Tracker to capture the dolly movement. Instead it interprets the 
> camera movement as a pan.
> 
> I believe if I can somehow use my 2D tracking information and apply it to the 
> camera, I can use that inside my 3D app. Any suggestions?
> 
> Thanks in advance.
> 
> 
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