Hi, You can use ones as well if the array (not matrix) has the same values, or the array function to create an array from a sequence, or matrix for matrix and a sequence of sequences
a = n.ones((3,5)) * 99999 b = n.array((1, 2, 3), (4, 5, 6), (6, 7, 8)) c = n.matrix((1, 2, 3), (4, 5, 6), (6, 7, 8)) Matthieu 2007/12/21, [EMAIL PROTECTED] <[EMAIL PROTECTED]>: > > hi > i am a beginner with numpy and python,so pardon me if this doubt seems > silly > i want to create a matrix with say 3 rows and 5 columns..and then set > the values of each item in it .for this i did something like below > > myarray=zeros((3,5)) > #then set the items > for row in range(3): > for col in range(5): > myarray[row][col]=999999.9999 > > > mymatrix=matrix(myarray) > > is this the way to do the matrix creation and value setting? is the > use of zeros() unnecessary? i am in the early learning stage so > your reply wd help me much > > dn > _______________________________________________ > Numpy-discussion mailing list > Numpy-discussion@scipy.org > http://projects.scipy.org/mailman/listinfo/numpy-discussion > -- French PhD student Website : http://matthieu-brucher.developpez.com/ Blogs : http://matt.eifelle.com and http://blog.developpez.com/?blog=92 LinkedIn : http://www.linkedin.com/in/matthieubrucher
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