or, you can either use fill.
In [53]: M = numpy.matrix(numpy.zeros((3,5)))
In [55]: M.fill(999)
In [56]: M
Out[56]:
matrix([[ 999., 999., 999., 999., 999.],
[ 999., 999., 999., 999., 999.],
[ 999., 999., 999., 999., 999.]])
L.
On 12/21/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
>
> hi
> i am a beginner with numpy and python,so pardon me if this doubt seems
> silly
> i want to create a matrix with say 3 rows and 5 columns..and then set
> the values of each item in it .for this i did something like below
>
> myarray=zeros((3,5))
> #then set the items
> for row in range(3):
> for col in range(5):
> myarray[row][col]=999999.9999
>
>
> mymatrix=matrix(myarray)
>
> is this the way to do the matrix creation and value setting? is the
> use of zeros() unnecessary? i am in the early learning stage so
> your reply wd help me much
>
> dn
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> Numpy-discussion@scipy.org
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>
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