On Sat, Jun 21, 2008 at 7:39 AM, Travis E. Oliphant <[EMAIL PROTECTED]> wrote:
> Charles R Harris wrote: > > Shouldn't this raise an NotImplementedError exception? > > > > In [7]: type(remainder(complex192(1), complex192(1))) > > Out[7]: <type 'NotImplementedType'> > I'm not sure if it is relevant in this case but we do need to keep in > mind that Python uses the NotImplementedType as a signal to hand off the > calculation to the other object in a binary operation. > > If we change this here we may affect that behavior, unintentionally. > But Python only does that if the Py_TPFLAGS_CHECKTYPES bit in the tp_flag is set. With that flag it should try with the other variable, then raise a Type error if that fails also. That's why I think the flag isn't set for these variables; we should never see the NotImplementedType. And at first glance at the code, I don't think that flag *is* set for the type. Chuck
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