On Fri, Mar 19, 2010 at 7:53 AM, gerardob <gberbeg...@gmail.com> wrote: > > Hello, i would like to produce lists of lists 1's and 0's. > > For example, to produce the list composed of: > > L = [[1,0,0,0],[0,1,0,0],[0,0,1,0],[0,0,0,1]] > > I just need to do the following: > > n=4 > numpy.eye(n,dtype=int).tolist() > > I would like to know a simple way to generate a list containing all the > lists having two 1's at each element. > > Example, n = 4 > L2 = [[1,1,0,0],[1,0,1,0],[1,0,0,1],[0,1,1,0],[0,1,0,1],[0,0,1,1]] > > Any ideas? > Thanks.
Here's the brute force way: >> for i in range(4): ....: for j in range(i+1, 4): ....: x = np.zeros(4) ....: x[i] = 1 ....: x[j] = 1 ....: print x ....: ....: [ 1. 1. 0. 0.] [ 1. 0. 1. 0.] [ 1. 0. 0. 1.] [ 0. 1. 1. 0.] [ 0. 1. 0. 1.] [ 0. 0. 1. 1.] _______________________________________________ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion