On Fri, Mar 19, 2010 at 10:17 AM, Joe Kington <jking...@wisc.edu> wrote:
> See itertools.permutations (python standard library)
>
> e.g.
> In [3]: list(itertools.permutations([1,1,0,0]))
> Out[3]:
> [(1, 1, 0, 0),
> (1, 1, 0, 0),
> (1, 0, 1, 0),
> (1, 0, 0, 1),
> (1, 0, 1, 0),
> (1, 0, 0, 1),
> (1, 1, 0, 0),
> (1, 1, 0, 0),
> (1, 0, 1, 0),
> (1, 0, 0, 1),
> (1, 0, 1, 0),
> (1, 0, 0, 1),
> (0, 1, 1, 0),
> (0, 1, 0, 1),
> (0, 1, 1, 0),
> (0, 1, 0, 1),
> (0, 0, 1, 1),
> (0, 0, 1, 1),
> (0, 1, 1, 0),
> (0, 1, 0, 1),
> (0, 1, 1, 0),
> (0, 1, 0, 1),
>
>
>
> (0, 0, 1, 1),
> (0, 0, 1, 1)]
>
> Hope that helps,
> -Joe
>
>
If you use "set" you automatically eliminate replicates:
a = set(permutations([0,0,1,1]))
a
set([(0, 0, 1, 1),
(0, 1, 0, 1),
(0, 1, 1, 0),
(1, 0, 0, 1),
(1, 0, 1, 0),
(1, 1, 0, 0)])
Converting back to a list:
b = list(a)
--
Gökhan
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